Question: For cases where A exactly doubles: if the rate does not change, the order for A is 0 . if the rate doubles, then the

For cases where

A

exactly doubles:\ if the rate does not change, the order for

A

is 0 .\ if the rate doubles, then the order for

A

is 1 .\ if the rate quadruples, the order for

A

is 2 .\ For more complex cases, use the general equation:\

(( rate _((

)

1))/(( rate _((

)

2))=(([ reactant ]_(1))/([ reactant ]_(2)))^(order )

\ What is the reaction order with respect to

A

?\ \\\\table[[,

[A],mo(l)/(L)

,

[B],mo(l)/(L)

,rate,

mo(l)/(L-min)
 For cases where A exactly doubles:\ if the rate does not

For cases where [A] exactly doubles: - if the rate does not change, the order for A is 0 . - if the rate doubles, then the order for A is 1. - if the rate quadruples, the order for A is 2 . For more complex cases, use the general equation: rate2rate1=([reactant]2[reactant]1)order What is the reaction order with respect to A ? Rate =k[A]orderA[B]orderB

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