Question: For each Environment, using data from Table 1.3, was used to perform the Shapiro Wilk test to assess whether data are normally distributed or not.
For each Environment, using data from Table 1.3, was used to perform the Shapiro Wilk test to assess whether data are normally distributed or not. Results for Environment at 15 C: W(14) = .8, p = .005, p-value equals 0.004969, W equals 0.7998, KS - D is large, 0.298. The Shapiro-Wilk test showed a significant departure from normality, Since p-value<, we reject the H0. It is assumed that the data is not normally distributed. In other words, the difference between the data sample and the normal distribution is big enough to be statistically significant. Since p-value<, we reject the null hypothesis. It is assumed that the data is not normally distributed. In other words, the difference between the data sample and the normal distribution is big enough to be statistically significant. The p-value means that the chance of type I error is small . The smaller the p-value the more it supports the working hypothesis. The test statistic is not in the 95% region of acceptance. The observed effect size. This indicates that the magnitude of the difference between the sample distribution and the normal distributions is large. Explain
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