Question: For each OCaml type, give a function that has the type as its most general type (e.g., if the type is 'a -> 'a, the

For each OCaml type, give a function that has the type as its most general type (e.g., if the type is 'a -> 'a, the answer could be fun x -> x, but not fun x -> x + 1, as that has most general type int -> int. (a) (3 points) 'a -> 'a option (b) (3 points) int * int -> int (c) (3 points) 'a -> 'b -> 'b * 'a
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