For the area shown in the figure, use integration to determine the x and y positions of the centroid. Take x1 = 20 mm and x2 = 25 mm. Consider constant k, where k=1mm (constraints are y=x-x^2/40 and y=-30+2x )The x location of the centroid is mm and the y location of the centroid is mm
 

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y y = x- kx2/40 10 mm y = -30+2x X. X1 X2 y y = x- kx2/40 10 mm y = -30+2x X. X1 X2