For the circuit shown below, find the voltage v$\_(0)($t$)$ if v$\_(1)($t$)=10$cos$(6000$t$+53\mathrm{.}13\backslash$deg $)$V and v$\_(2)($t$)$

$=8$cos$(6000$t$-90\backslash$deg $)$V$.$

Note v$2$ has a different polarity direction than v$1$