Question: For the differential amplifier, vG 1 = 0 . 9 V + 0 . 1 V sin ( t ) and vG 2 = 0

For the differential amplifier, vG1=0.9 V +0.1 V sin(t) and vG2=0.9 V -0.1 V sin(t). The common-mode voltage is
Group of answer choices
0.9 V
1.0 V
0.8 V
0.1 V sin(t)
-0.1 V sin(t)
0.2 V sin(t)
-0.2 V sin(t)

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