For the differential equation $y^{\text{'}\text{'}}-8y^{\text{'}}+16y=0,$ a general solution $isof$ the form

$y=C_1{e}^{4x}+C_{2}x{e}^{4x},$ where $C_1$ and $C_2$ are arbitrary constants.

Applying the initial conditions $y(0)=1$ and $y^{\text{'}}(0)=8,$ find the specific solution.

$y=$