Question: For the function f ( x , y ) = 2 x ^ 2 - 2 xy + y ^ 2 - y + 3

For the function
f(x, y)=2x^2-2xy + y^2- y +3
a) Find any ordinary critical points and determine whether they are maxima, minima or saddle points.
b) On the closed triangle R with vertices (0,0),(2,0) and (0,2) find any possible local maxima or minima on the boundary of R.
c) Using the results from part a) and b), find the global (absolute) maximum and minimum of f(x, y) and give the values of f(x, y) at these points.
The second derivative test for f(x, y), where d1= fxx and d2= det Hf
d2>0 and d1>0: Local Minimum
d2>0 and d1<0: Local Maximum
d2<0 : Saddle Point
d2=0 : Can't determine type by this method

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