Question: For the given two reactions (1) Cu2O + 2H+ + 2e = 2Cu + H20 (E = 0.471 V SHE) and (2) CuO + 2H+

For the given two reactions (1) Cu2O + 2H+ + 2e = 2Cu + H20 (E = 0.471 V SHE) and (2) CuO + 2H+ + 2e = Cu2O + H20 (E = 0.471 V SHE) In a Pourbaix diagram of Cu, the reaction (1) and the reaction (2) can be represented as: (A) The same line because both reaction (1) and reaction (2) have different electrode potential (B) The different line because both reaction (1) and reaction (2) have different electrode potential (C) The same line because both reaction (1) and reaction (2) have same electrode potential (D) The different line because reaction (1) is a vertical line and reaction (2) is a sloping line (E) None of the above
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