Question: For the problem, max 811 + 1212 s.t. x1 + 312 = 10, 2:1 + 412 For the problem, max + 12X2 s.t- + 3C2

For the problem, max + 12X2 s.t- + 3C2 10, 2X1 +

For the problem, max 811 + 1212 s.t. x1 + 312 = 10, 2:1 + 412

For the problem, max + 12X2 s.t- + 3C2 10, 2X1 + 4t2 16, 0, t2 0, the solution for is the solution for is , the price for the first constraint is , and the price for the second constraint is (Enter your answers as numbers in the boxes]

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