For the programme example given below, show the stack state $($activation record instance$)$ according to deep and shallow access methods.

main calls sub$1$

sub$1$ calls sub$1$

sub$1$ calls sub$2$

sub$2$ calls sub$3$

void sub$3()\{$

int x$,$ z;

x $=$ u $+$ v;

$...$

$\}$

void sub$2()\{$

int w$,$ x;

$...$

$\}$

void sub$1()\{$

int v$,$ w;

$...$

void main$()\{$

int v$,$ u;

$...$

$\}$