Question: For the section, I z ' = 3 1 . 7 ( 1 0 - 6 ) m 4 , I y ' = 1

For the section, Iz'=31.7(10-6)m4,Iy'=114(10-6)m4,Iy'z'=-15.8(10-6)m4. The member's cross-sectional area has principal moments of inertia of Iz=28.8(10-6)m4 and Iy=117(10-6)m4, calculated about the principal axes of inertia y and z, respectively. (Figure 1)
Figure
1 of 1
Part A
If the section is subjected to the moment M=13kN*m, determine the stress at point A using =-M2yf2+M12y12
Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension.
A=
For the section, I z ' = 3 1 . 7 ( 1 0 - 6 ) m 4

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mechanical Engineering Questions!