Question: For two reactions: A+B yielding C+D(Delta G ) = ( +35(J)/(m)ole) C+D yielding E+F(Delta G ) = ( -40(J)/(m)ole) What is the Delta

For two reactions:\

A+B

yielding

C+D(\\\\Delta G

)

=

(

+35(J)/(m)ole)

\

C+D

yielding

E+F(\\\\Delta G

)

=

(

-40(J)/(m)ole)

\ What is the

\\\\Delta G

for the combined reaction

A+B

yielding

E+F

?\

+75(J)/(m)ole

\

-75(J)/(m)ole

\

-5(J)/(m)ole

\

+5(J)/(m)ole
 For two reactions:\ A+B yielding C+D(\\\\Delta G) =( +35(J)/(m)ole)\ C+D yielding

For two reactions: A+B yielding C+D(G=+35J/ mole ) C+D yielding E+F ( G=40J/ mole) What is the G for the combined reaction A+B yielding E+F ? + 75J/mole 75J/mole 5J/ mole +5 J/mole

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