Question: For two reactions: A+B yielding C+D(Delta G ) = ( +35(J)/(m)ole) C+D yielding E+F(Delta G ) = ( -40(J)/(m)ole) What is the Delta
For two reactions:\
A+Byielding
C+D(\\\\Delta G)
=(
+35(J)/(m)ole)\
C+Dyielding
E+F(\\\\Delta G)
=(
-40(J)/(m)ole)\ What is the
\\\\Delta Gfor the combined reaction
A+Byielding
E+F?\
+75(J)/(m)ole\
-75(J)/(m)ole\
-5(J)/(m)ole\
+5(J)/(m)ole 
For two reactions: A+B yielding C+D(G=+35J/ mole ) C+D yielding E+F ( G=40J/ mole) What is the G for the combined reaction A+B yielding E+F ? + 75J/mole 75J/mole 5J/ mole +5 J/mole
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