For what value$($s$)$ of $x$ does the function $f(x)=ln(x^2+3)$

have the property that the line tangent to the curve has a

slope of $\frac{1}{2}?$

$x=(\sqrt[\phantom{2}]{e}-3{)}^{\frac{1}{2}}$ and $x=-(\sqrt[\phantom{2}]{e}-3{)}^{\frac{1}{2}}$

$x=1$ and $x=3$

$x=(\sqrt[\phantom{2}]{e}-3{)}^{\frac{1}{2}}$ only

$x=1$ only

$x=e$ only