Question: From the question above, I have calculated and obtained v= 1-t 4 But the exact solution for v is approximated by the polynomial as shown

 From the question above, I have calculated and obtained v= 1-t4

From the question above, I have calculated and obtained v= 1-t4

But the exact solution for v is approximated by the polynomial as shown below.

Using Euler's method or other methods, what is the comment on accuracy of the approximation?

But the exact solution for v is approximated by the polynomial as

V The variables v and t are related by the differential equation dav 2 + dt2 + 6t2 = 0, where v(0) = 1,v'(0) = 0,v > 0. dt dv Solve for v in terms of t by setting z = VT 1 1 8 12. p1 = 1 -2 - 16 V The variables v and t are related by the differential equation dav 2 + dt2 + 6t2 = 0, where v(0) = 1,v'(0) = 0,v > 0. dt dv Solve for v in terms of t by setting z = VT 1 1 8 12. p1 = 1 -2 - 16

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