From this figure and by using this equation

$\frac{dy}{dx}=\frac{M_0}{\text{E}\text{I}\text{L}}(\frac{1}{2}{x}^2-Lx+\frac{1}{3}{L}^2),y=\frac{M_0}{\text{E}\text{I}\text{L}}(\frac{1}{6}{x}^3-\frac{1}{2}L{x}^2+\frac{1}{3}{L}^{2}x)$

$1-$ The location maximum deflection, of beam $AB$ s :

a$)L$

b$)0\mathrm{.}763L$

c$)0\mathrm{.}423L$