Function Point f(x) = (28-x2)2/3 (1,9) (a) Find an equation of the tangent line to the...

Transcribed Image Text:

Function Point f(x) = (28-x2)2/3 (1,9) (a) Find an equation of the tangent line to the graph of the function at the given point. (Let x be the independent variable and y be the dependent variable. y= x + 79 9 X (b) Use a graphing utility to graph the function and its tangent line at the point. Function Point f(x) = (28-x2)2/3 (1,9) (a) Find an equation of the tangent line to the graph of the function at the given point. (Let x be the independent variable and y be the dependent variable. y= x + 79 9 X (b) Use a graphing utility to graph the function and its tangent line at the point.

Answer rating: 100% (QA)

fx 28x fx 15 filxy l b at x1 Hence tangent ... View the full answer