Question: Function Point f(x) = (28-x2)2/3 (1,9) (a) Find an equation of the tangent line to the graph of the function at the given point.

Function Point f(x) = (28-x2)2/3 (1,9) (a) Find an equation of the

Function Point f(x) = (28-x2)2/3 (1,9) (a) Find an equation of the tangent line to the graph of the function at the given point. (Let x be the independent variable and y be the dependent variable. y= x + 79 9 X (b) Use a graphing utility to graph the function and its tangent line at the point.

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