Question: f(x) ) = cos(6x - ex-9) f'(x) = f(x) = exp(x6 - 6 cos(x)) '(x) = f(x) = 6ex sec9x) f'(x) = Note: You





f(x) ) = cos(6x - ex-9) f'(x) = f(x) = exp(x6 - 6 cos(x)) '(x) = f(x) = 6ex sec9x) f'(x) = Note: You can earn partial credit on this problem. f(x) = 4x+6 f'(x) = f(x) = 7 8+5x f'(x) = f(x) = 4x-6 f'(x) = Note: You can earn partial credit on this problem. TH U T T g(s) = exp(tan (s)) g' (s) = h(t) = 52t +7 h'(t) = f(t) = 9 9t-9 f' (t) = Note: You can earn partial credit on this problem. f(x) = f'(x) = f(x) = f'(x) = 9x + e-8x 2+xe-8x 9x e-8x + e8x f(x) = ecos(8x-9) f'(x) = m T g(r) = 8-2 sin(r) g' (r) = g(r) = 3r/ g (r) =
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