Question: fX2 = (0.15 X)(0.050) = (0.15 * 0.050) 0.050X - Or in terms of general quadratic equation ax2 + bx + c = 0 x2

\fX2 = (0.15 X)(0.050) = (0.15 * 0.050) 0.050X - Or in terms of general quadratic equation ax2 + bx + c = 0 x2 + 0.050x 7.5 x 10-3 = o - Where a = 1, b = 0.050, and c = - 7.5 x 10-3 - Now ut into uadratic formula p q X_bJ_rx/b24ac _ 2a X _ 2(1) - x= 0.065 Mand x= 0.115 M

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