g (x) = (x^2 - 6x + 13)/4 if x 1 and 2squareroot(2-x) if x

v) (8 points) Evaluate lim 8(x) - g(1) x -+1+ x - 1 lim 8(x) - 8(1) = x-+1 x - 1 vi) (2 points) Use your answers from above to find the value of g'(1), if it exists. If g'(1) does not exist, explain why. [Hint: Use the limit definition of the derivative g'(1).] g' (1 ) = vii) (4 points) Find an equation for the line tangent to g(x) at x = 1, if this line exists. If this tangent line does not exist, explain why. Equation: h) (4 points) In this homework, we found g'(0) by evaluating a single two-sided limit. However, we found g'(1) by evaluating two different one-sided limits. Why did we need to calculate g'(1) and g'(0) using such different methods