Question: gamma _ ( f ) = 8 0 l ( b ) / ( f ) t ^ ( 3 ) , mu

\gamma _(f)=80l(b)/(f)t^(3),\mu =0.03lb*(s)/(f)t^(2) D=2in.\Delta h=0.2in. The specific weight of gage fluid inside the
manometer, \gamma =100l(b)/(f)t^(3) and distance between
"1" and "2", l=6 in.
Determine:
a\Delta p=p_(1)-p_(2)? Hint: FEHS is
applicable for the liquid in the manometer.
bQ(f(t^(3))/(s))?
cu_(max)(f(t)/(s))?
\ gamma _ ( f ) = 8 0 l ( b ) / ( f ) t ^ ( 3 ) ,

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