GE$15$

Propanoic acid $($C$.$H$.$COOH$)$ CH$+$ CHOOH $($CH$-$COOH$)($CH$)($CHOOH$)1$:$210$ Ls$\text{'}$ a$)$ k $=4(10$ L mol's. $80\%5$ mol s$\text{'}(10)$ b$)$ k $=3$ L$$kgcat$\text{'}$ mol's. $523$K $5$ atm $$ D $=1506=10$ m$(=0\mathrm{.}5(=3000$ kg m$\text{'}$ D$.=5$: C$2$H$4$: CHOOH $94$:$2$:$4(<0\mathrm{.}05.$