Given $a=7m,b=6m,c=9m,d=0\mathrm{.}3m,e=5,f=3,g=4,=25,F_1=42N,F_2=27N,$ and $F_3=39N,$

$F_3$

determine the magnitude of the moments produced at point $B$ from each force.

$(M_{F_1}{)}_B=$

Nm

Your last answer was interpreted as follows:

$(M_{F_2}{)}_B=$

Vm

Your last answer was interpreted as follows:

$(M_{F_3}{)}_B=$

Vm

$124$