Given a dictionary d and a list lst, remove all elements from the dictionary whose key is an element of lst. Any elements from the list that are NOT keys of the dictionary should be added to a new set associated with the variable not_found. For example, given the dictionary {1:2, 3:4, 5:6, 7:8} and the list [1, 6, 7], the resulting dictionary would be {3:4, 5:6} and the set not_found would contain 6.

In Python