Given a subnet mask /24, how many host addresses can this network support? (remember some are reserved)

8

254

24

256

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Question 25 pts

Which is the correct IPv6 address using the corresponding EUI-64 for device with MAC address of 00-22-D9-C4-B5-89 on network FF0C::010C?

FF0C::010C:0022:D9C4:B589:0000

FF0C::010C:0022:D9C4:B589

FF0C::010C:0222:D9FF:FEC4:B589

FF0C::010C:0222:D9C4:B589:FFFE

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Question 35 pts

What is the loopback address?

255.255.255.255

192.168.255.255

127.0.0.1

192.168.0.1

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Question 45 pts

Given the IP: 192.168.32.100 and CIDR: /24, what is the host portion of this IP address?

192.168.32

168.32.100

100

192

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Question 55 pts

Given the IP: 192.168.32.100 and CIDR: /24, what is the network portion of this IP address?

192.168

168.32.100

192.168.32

32.100

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Question 65 pts

Which of the following networks has the largest amount of IP addresses for hosts?

/16

/32

/8

/24

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Question 75 pts

Given the IP: 146.186.32.100 and Subnet Mask: 255.255.0.0, what is the network portion of this IP address?

100

146.186

146

146.186.32

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Question 85 pts

IPv6 addresses are _______ bit binary numbers.

16

64

32

128

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Question 95 pts

Given the IP: 146.186.32.100 and Subnet Mask: 255.255.0.0, what is the CIDR notation?

146.186.32.0/24

146.186.32.100/24

146.186.0.0/16

146.0.0.0/8

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Question 105 pts

Given the IP: 146.186.0.0/24, what is a valid host address in this network?

146.186.255.50.

146.186.1.50

146.50.50.50

146.186.0.50

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Question 115 pts

Convert the decimal number 255 to binary.

1111 1111 1111

1111 1111

1111

1111 0000

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Question 125 pts

An IPv4 address is divided into parts: ______ and _______.

Physical and logical

Global and local

Network and host

Network and subnet mask

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Question 135 pts

The reason of for datagram fragmentation is to __________.

Accommodate heterogeneous MTUs

Reuse the same route

Improve transmission reliability

Balance network traffic

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Question 145 pts

Host A sends a datagram to host B through network #1 (MTU = 1000 bytes), network #2 = (MTU = 1200 bytes), and network #3 (MTU = 1500 bytes). What is the path MTU from host A to host B?

1200 bytes

3700 bytes

1000 bytes

1500 bytes

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Question 155 pts

IP datagrams are _________________.

Different depends on the type of transmission media

Different depends on the Network Interface Layer protocol

The same format regardless the underlying network

Different depends on the type of network

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Question 165 pts

With regard to datagram fragmentation, which of the following is correct?

Datagram fragmentation is always performed

Datagram fragmentation happens only when the datagram exceeds MTU.

Sending host determines whether to perform datagram fragmentation or not.

Router determines whether to perform datagram fragmentation or now.

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Question 175 pts

Host A sends a datagram (length = 1200 bytes) to host B through network #1 (MTU = 1000 bytes), network #2 = (MTU = 1200 bytes), and network #3 (MTU = 1500 bytes). How many fragment(s) will be delivered to host B assuming there is no loss or duplicate?

1

4

3

2

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Question 185 pts

Destination	Mask	Next Hop
120.130.55.0	255.255.255.0	120.130.55.10
54.87.0.0	255.255.0.0	54.87.10.10
128.1.0.0	255.255.0.0	deliver directly
92.63.0.0	255.255.0.0	92.63.10.10
92.63.20.0	255.255.255.0	92.63.20.10

According to the forwarding table above, what should the router do when it receives 54.87.14.9?

Deliver the datagram to a host in the network

Forward the datagram to 92.63.10.10

Forward the datagram to 120.130.55.10

Forward the datagram to 54.87.10.10

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Question 195 pts

Host A sends a datagram (length = 2200 bytes) to host B through network #1 (MTU = 1000 bytes), network #2 = (MTU = 1200 bytes), and network #3 (MTU = 600 bytes). How many fragment(s) will be delivered to host B assuming there is no loss or duplicate?

2

1

3

4

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Question 205 pts

What does the router do when it receives a datagram that matches more than one entry in the forwarding table?

Remove all but one entry in the forwarding table and forward the datagram to next hop

Forward the datagram to anyone entry that matches

Discard the datagram

Use longest prefix match and forward it to next hop