Given an array of 2 integers, write a MIPS program to implement some ALU operations and store the results back to memory. The C code below shows how the elements are appended to the array: // Declaration of variables int* A; // Integer array A with the base address pointing to variable A int a; char b, c; short d; // Append array elements { A[2], A[4] } = A[1] * A[0]; // {} = concatenation / append. 64-bit product should be stored in Array A[5] = A[4] / 230; a = A[4] % 230; b = a >> 16; // '>>' = right shift c = (a & 0b'1000) | (b | 0b'0011); // '&' = bit-wise and d = a << 2; // '<<' = left shift A[6] = {b, c, d}; // {} = concatenation / append. Use Memory Operations (identify the correct address to place, c and d in Array) A[3] = (A[0] + A[1] - 100) - (A[2] + A[4] - A[5])