2. A solid round steel rod 1.25 inches in diameter and 6.25 inches long is rigidly...

 

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2. A solid round steel rod 1.25 inches in diameter and 6.25 inches long is rigidly connected to the end of a solid square brass rod 1.50 inches on a side and 8.50 inches long. The geometric axes of the bars are along the same line. Two axial forces are applied. A force of 30.0 kip is applied at the end of the assembly, and a 90.0 kip force is applied at the junction of the assembly. For steel, the modulus of elasticity is 30 x 106 psi and for brass it is 16 x 106 psi. Determine: a. What is the internal force in the steel? What is the internal force in the brass? b. c. What is the stress in the round steel rod? d. What is the stress in the square brass rod? e. If the yield strength in the steel is 36 ksi, and the yield strength in the brass is 60 ksi, and that buckling is not a concern. What is the factor of safety for the assembly? 30.0 kip 90.0 kip 2. A solid round steel rod 1.25 inches in diameter and 6.25 inches long is rigidly connected to the end of a solid square brass rod 1.50 inches on a side and 8.50 inches long. The geometric axes of the bars are along the same line. Two axial forces are applied. A force of 30.0 kip is applied at the end of the assembly, and a 90.0 kip force is applied at the junction of the assembly. For steel, the modulus of elasticity is 30 x 106 psi and for brass it is 16 x 106 psi. Determine: a. What is the internal force in the steel? What is the internal force in the brass? b. c. What is the stress in the round steel rod? d. What is the stress in the square brass rod? e. If the yield strength in the steel is 36 ksi, and the yield strength in the brass is 60 ksi, and that buckling is not a concern. What is the factor of safety for the assembly? 30.0 kip 90.0 kip

Answer rating: 100% (QA)

a To find the inte rnal force in the steel we need to calculate the elongation of the entire assembl... View the full answer