Question: Given: Cu+ + 2e Cu NO3 + 4H+ + 3e NO + 2 HO calculate the value of E, in volts, for the reaction:

Given: Cu+ + 2e Cu NO3 + 4H+ + 3e NO +

Given: Cu+ + 2e Cu NO3 + 4H+ + 3e NO + 2 HO calculate the value of E, in volts, for the reaction: 3 Cu + 2 NO3 + 8 H+ 3 Cu+ + 2 NO + 4 HO cell V E = +0.34 V E = +0.96 V Note: Include a sign for your calculated answer. (ie. +1.0 or -1.0)

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