Given f$\text{'}$ c $=30$ MPa

Fy $=400$

Interior exposure

aggregate size $=20$

shear steel $=$ #$10$ bar

Beta $=0\mathrm{.}88$

p bal $=2\mathrm{.}63$

Design a beam to span $15$ meters. The total factored udl on the beam is $18$

KN$/$m$.$ Design for approximately $40\%$ of balanced steel

ANSWERS should be

Final beam: h$"\text{'}740$ mm$.,$ b$=345$ mm$.,$ d$=687\mathrm{.}5$ mm$.,$ shear steel$$# $10$ bars, moment rebar $=5$ #$25,$

M$,=513$ KN$-$m $>$ M$,=506$ KN$-$m therefore ok$,$ actual bar spacing $=35$ mm$,$ required bar spacing $=35$ mm therefore

ok; actual reinforcement ratio $=1\mathrm{.}05($within $+/-5\%$ of target$)$