Question: Given f(x) = 2x - 14x + bx - 3 has zero x =2, and g(x) = x + cx2- 3x + 10, with ca

 Given f(x) = 2x - 14x + bx - 3 has

zero x =2, and g(x) = x + cx2- 3x + 10,

Given f(x) = 2x - 14x + bx - 3 has zero x =2, and g(x) = x + cx2- 3x + 10, with ca real number, has zero x = 2 - i, find (f . g)( - 1). (f . 9)( - 1) = (Simplify your answer.)

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