Question: Given f(x, x2) = x + xx2 + (1+x2) for x, x2 ER, apply inverse SR-I update rule to f(1, 2) [8] .H. - (669)

Given f(x, x2) = x + xx2 + (1+x2) for x, x2 ER, apply inverse SR-I update rule to f(1, 2) [8] .H. - (669) Hk (ad) = with ki of a. -1 0 1/3 -1/3 2/3 = -2/3 1 None of them ak= 2 to obtain the next iteration Hk+1 = Find the value
 Given f(x, x2) = x + xx2 + (1+x2) for x,

Given f(x1,x2)=x12+x1x2+(1+x2)2 for x1,x2R, apply inverse SR-I update rule to f(x1,x2) with xk=[00],Hk=(1001),k=21 to obtain the next iteration Hk+1=(acbd). Find the value of a. 1 0 1/3 1/3 2/3 2/3 1 None of them

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