Question: Given list: (0,1,10,27,33,50,58,70,79,86,90) Which list elements will be compared to key: 0 using binary search? (comma between values) 0 using linear search? 90 using binary

Given list: (0,1,10,27,33,50,58,70,79,86,90) Which list elements will be compared to key: 0 using binary search? (comma between values) 0 using linear search? 90 using binary search? 90 using linear search? Which search method is faster to find 0 ? Which search method is faster to find 90 ? \begin{tabular}{|l|l|l|} \hline 1 & 2 & 3 \\ \hline \end{tabular}
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