Given

$s^6=x^3+2$

Using implicit differentiation, $\frac{dx}{ds}is$ found $tobe$:

$\frac{dx}{ds}=$

$\frac{2s^5}{x^2}$

$\frac{s^6-2}{x^3}$

$\frac{x^3+2}{s^6}$

$\frac{x^2}{2s^5}$

None $of$ the above.