Question: Given that 8g(x)+7x sin(g(x)) = 8x + 41x - 42 and g() = 0, find g(). d' (33) =

Given that 8g(x)+7x sin(g(x)) = 8x + 41x - 42 and g()

Given that 8g(x)+7x sin(g(x)) = 8x + 41x - 42 and g() = 0, find g(). d' (33) =

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