Question: Given that 8g(x)+7x sin(g(x)) = 8x + 41x - 42 and g() = 0, find g(). d' (33) =
Given that 8g(x)+7x sin(g(x)) = 8x + 41x - 42 and g() = 0, find g(). d' (33) =
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Solution Solution 8 gx 7x singx 7x singx 8 x41... View full answer
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