Given that C(s) + O2(g) --> CO2(g) Delta G =-394.4 kj 2CO(g) + O2(g) --> 2CO2(g) DeltaG

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Given that

C(s) + O2(g) --> CO2(g) Delta G =-394.4 kj

2CO(g) + O2(g) --> 2CO2(g) DeltaG = -514.4 kj

calculate the DeltafG of carbon monoxide.

C(s) + 1/2 O2(g) --> CO(g)

Answer is -137.2 kj Please show steps on how to get this.

Related Book For answer-question

Chemical Principles

ISBN: 978-1111580650

7th edition

Authors: Steven S. Zumdahl, Donald J. DeCoste

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Posted Date: Nov 30, 2022 02:20 AM

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Given that C(s) + O2(g) --> CO2(g) Delta G =-394.4 kj 2CO(g) + O2(g) --> 2CO2(g) DeltaG

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1 Cs 02 g coz g DG1 3944 kJ 5144 kJ 2 2 cog 02g 2 CO2g DG2 Reve... View the full answer

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