Question: Given that the acceleration vector is a(t) = (-9 cos(-3t))i + (-9sin(-3t))j + (-t)k, the initial velocity is v(0) = i + k, and the

Given that the acceleration vector is a(t) = (-9 cos(-3t))i + (-9sin(-3t))j + (-t)k, the initial velocity is v(0) = i + k, and the initial position vector is r(0) = i + j + k, compute: A. The velocity vector v(t) = -3 sin (-3t) -3 cos (-31) k B. The position vector r(t) = cos( -3t it sin (-3t) k

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