Question: Please explain Given that the acceleration vector is a (t) = (-9cos(-3t))i + (-9sin(-3t))j + (5t)k, the initial velocity is v (0) = i +

Please explain

Given that the acceleration vector is a (t) = (-9cos(-3t))i + (-9sin(-3t))j + (5t)k, the initial velocity is v (0) = i + k, and the initial position vector is r (0) = i + j + k, compute: A. The velocity vector v (t) = it j+ k B. The position vector r (t) = it j+ k Submit answer Next item

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