Given that $x_0=-1$ and $x_1=1.$ Then the basis of the first Lagrange polynomial $L_0(x)$ and $L_1(x)$ are respectively

Select one:

a$.0\mathrm{.}50\mathrm{.}5x$ and $0\mathrm{.}5x0\mathrm{.}5$

b$.0\mathrm{.}5-0\mathrm{.}5x$ and $0\mathrm{.}5x-0\mathrm{.}5$

c$.0\mathrm{.}5-0\mathrm{.}5x$ and $0\mathrm{.}5x0\mathrm{.}5$

d$.0\mathrm{.}50\mathrm{.}5x$ and $0\mathrm{.}5x-0\mathrm{.}5$