Question: : Given that y1 = t and y2 = e^t are linearly independent solutions to y + [t/(1-t) ] y' - [1/(1-t) ] y

: Given that y1 = t and y2 = e^t are linearly

: Given that y1 = t and y2 = e^t are linearly independent solutions to y" + [t/(1-t) ] y' - [1/(1-t) ] y = 0 for t > 1, use variation of parameters to find the general solution to y" + [t/(1-t) ] y' - [1/(1-t) ]y=(t-1) e^t

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