Given the array definitions arr: $.$byte $1,2,-3,4$; After executing the following code, the

content of the three registers $$t1,$$$t2,$ and $$t3$ will be:

Assume that the instruction bne $$t,$$$t1,$NExT is address $x0040002$ in the text segment, and

the label NEXT is at address $00400010.$ Then, the address stored in the assembled instruction for the

label NEXT is $,\frac{0x00400010-(0x00400020+4)}{4}=0xfffb$