Question: ` ` ` Given the C code ( pseudo - code ) , inputs: byte A [ 1 6 ] , go ( 1 bit

```
Given the C code (pseudo-code),
inputs: byte A[16], go (1 bit),
outputs: count (5 bits), done (1 bit)
while(1){
while(!go);
done =0;
count =0;
i =0;
while(i16){
temp = A[i];
if((temp >47) && (temp 58)){
count++;
A[i]= temp -48;
}
i=i +1;
}
done =1;
}
```
Part A
A.1) Convert the C code to HLSM diagram.
` ` ` Given the C code ( pseudo - code ) ,

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