Given the @D array in class AdoptionRunner: Pet$[][]$ pets $=\{\{$new Pet$("$Dog$",2),$ new Pet$("$Dog$",5),$ new Pet$("$Dog$",8)\},$

$\{$new Pet$("$Hamster$",1),$ new Pet$("$Hamster$",2),$ new Pet$("$Hamster$",3)\},$

$\{$new Pet$("$Bird$",5),$ new Pet$("$Bird$",7),$ new Pet$("$Bird$",12)\}\}$; In the Adoption class, write the reversePets$()$ method to reverse the elements in the row at the parameter index in the $2$D array pets. public class Adoption $\{$

private Pet$[][]$ pets; $//$ The $2$D array of Pet objects

$/*$

$*$ Initializes pets to the specified $2$D array of Pet objects

$*/$

public Adoption$($Pet$[][]$ pets$)\{$

this.pets $=$ pets;

$\}$

$/*$

$*$ Returns the $2$D array of Pet objects

$*/$

public Pet$[][]$ getPets$()\{$

return pets;

$\}$

$/*$

$*$ Reverses the row located at index by swapping the first

$*$ and last elements in the row

$*/$

public void reversePets$($int index$)\{$

$\}$

$/*$

$*$ Returns a String containing the information for

$*$ each Pet object in the $2$D array pets

$*/$

public String toString$()\{$

String result $=""$; for $($int row $=0$; row $<$ pets.length; row$++)\{$

for $($int col $=0$; col $<$ pets$[0].$length; col$++)\{$

result $+=$ pets$[$row$][$col$]+""$;

$\}$

result $+="$

$"$;

$\}$

return result;

$\}$

$\}$