Given the following C code: $[1$ #include $$stdio$.$h$$; $2$ ; $3$ int; $4$ main $()$; $5=$ ; $6$ ; $7$ int UCSC $=-12$ ;; $8$ int $*$cse$12=$ &UCSC;; $9$ ; $10$ printf $("\%$d $\%$d$",$ UCSC, $*$cse$12)$;; $11$ ; $12$ ; $13$ return $\backslash$theta ;; $14\}]$ #include $$stdio$.$h$$ int main $()\{$ int UCSC$=-12$; int $*$ cse $12=$ &UCSC; printf $("\%$d $\%$d$",$ UCSC, $*$cse$12)$; return $\backslash$theta ; $\}$ What is the output generated when we run this code through using the printf statement? NOTE: the printf$()$ in C is pretty much the same as the print$()$ in Python. Except here, you also need to specify what type of data you are printing. The $"\%$d $\%$d$"$ implies we are printing $8$ byte long integers in base $10,$ first the data UCSC, and then the date $*$cse$12.-12$ undefined $-12-12-120$xFFFF FFFF FFFF FFF$40$xFFFF FFFF FFFF FFF$40$xFFFF FFFF FFFF FFF$4$