Question: Given the following C program. # include void vector_input(float v[], int n); void vector_output(float v[], int n); void vector_add(flaot v1[], float v2[], float v3[], int
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Given the following C program. # include void vector_input(float v[], int n); void vector_output(float v[], int n); void vector_add(flaot v1[], float v2[], float v3[], int n); void vector_multiply(float v[], int n, flaot x); float inner_product(float v1[], float v2[], int n); float length(float v[], int n); int main(); {return 0;} void vector_input(float v[], int n) {} void vector_output(float v[], int n) {} vector_add(flaot v1[], float v2[], float v3[], int n) {} void vector_multiply(float v[], int n, flaot x) {} float inner_product(float v1[], float v2[], int n) {}); float length(float v[], int n) {} void vector_nput(float v[], int n): input the elements of vector v and store in the array. void vector .output (float v[], int n): output the elements of vector v on the screen. void vector_add(float vl[], float v2[], float v3[], int n): calculate the sum of vector v1 and v2 and store the result in v3. The sum is a vector, not a single value. void vector_multiply(float v[], int n, float x): multiply each element in v by x float inner_product(float vl [], float v2[], int n): return the inner product of vector vl and v2. float length(float v[], int n): return the length of vector v vector .add: (1.2, 3.5, 5.7)+(3.2, 1, 6.3)=(4.4, 4.5, 12) vector_multiply: (2.2, 4.1, 6.5)times3=(6.6, 12.3, 19.5) inner.product: (l, 2, 3)-(4, 5, 6)=1 times 4 + 2 times 5+ 3 times 6 = 4 + 10 + 18 = 32 length: length of vector (3, 4, 5) is squareroot 9 + 16 + 25 = squareroot 50 = 7.071068