Given the following function: f$($x$)=4$x$^3-2$ use the $3-$point Gauss Quadrature to integrate the function with limits of integration, a$=-4,$ b $=4$ Recall that I $=$ integral from a to b f$($x$)$ dx $=$ integral from $-1$ to $1$ f$($x$)($b$-$a$)/2$ dx where x $=($b$+$a$)/2+($b$-$a$)/2$ x~ on top Please show all steps, including the change of variable.