Question: Given the following peicewise-defined functionf. f(x) = x^2+10 if -11 x < -3 19 if -3 x 5 -x^2+18 if 5 < x < 10

Given the following peicewise-defined functionf.

f(x) = x^2+10 if -11 x < -3

19 if -3 x 5

-x^2+18 if 5 < x < 10

Find the value(s) where the function is discontinuous on the interior of the domain, the open interval(11,10)(-11,10). If the function is continuous everywhere on(11,10)(-11,10), then inputDNE.

Discontinuous at x= ________________________

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