Question: Given the function 9(93) = 6:133 + 36582 90.22:, find the first derivative, 9 ' (51:). Notice that g'(a:) = 0 when a: = 5,

 Given the function 9(93) = 6:133 + 36582 90.22:, find the

Given the function 9(93) = 6:133 + 36582 90.22:, find the first derivative, 9 ' (51:). Notice that g'(a:) = 0 when a: = 5, that is, g'( 5) = 0. Now, we want to know whether there is a local minimum or local maximum at a: = 5, so we will use the second derivative test. Find the second derivative, 9' '(w). W) = Evaluate g' '( 5). g~=: Based on the sign of this number, does this mean the graph of 9(35) is concave up or concave down at a: = 5? At a: = 5 the graph of 9(113) iS Select an answer 0 Based on the concavity of g(:c) at a: = 5, does this mean that there is a local minimum or M maximum at :1: = 5? At (E = 5 there iS a local Select an answer 0

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