Question: I am having a hard time answering this question... Question 23 Given the function g(x) = 623- 63x2 4 180x, find the first derivative, 9'
I am having a hard time answering this question...

Question 23 Given the function g(x) = 623- 63x2 4 180x, find the first derivative, 9' (I) 9 (x) = Notice that g' (x) = 0 when x = 5, that is, g'(5) = 0. Now, we want to know whether there is a local minimum or local maximum at r - 5, so we will use the second derivative test. Find the second derivative, g' (x). 9 (x) = Evaluate g' (5). 9 (5) Based on the sign of this number, does this mean the graph of g(a) is concave up or concave down at x = 5? [Answer either up or down -- watch your spelling! !] At x = 5 the graph of g(r) is concave Based on the concavity of g() at x - 5, does this mean that there is a local minimum or local maximum at = = 5? [Answer either minimum or maximum -- watch your spelling! !] At x - 5 there is a local > Next
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