Question: Given the Python code:x = 0 ifx > 0 and ( 1 0 / x ) > 2 :print ( Valid ) else:print

Given the Python code:x =0ifx >0 and (10/x)>2:print("Valid")else:print("Invalid")Why does this code not result in a runtime error? Modify the code to avoid relying on short-circuit evaluation for safety.

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